|
Solve for y:
2y = 8
Step One: Knowing:
2y means multiply "y" by 2, and
division is the inverse operation
Step Two: Divide
both sides by 2 |
2y = 8
2y/2
= 8/2
y = 4 |
To check:
2y = 8
2(4) = 8
8 = 8√ |
|
Solve for y:
y/5 = 2
Step One: Knowing:
y/5 means divide "y" by 5, and
mulitplication is the inverse operation
Step Two: Multiply
both sides by 5
|
y/5 = 2
5(y/5)
= 5(2)
y = 10 |
To check:
y/5 = 2
10/5 = 2
2=2√ |
|
Solve for y:
y - 9 = 50
Step One: Knowing:
y - 9 means subtract 9 from "y" , and
addition is the inverse operation
Step Two: Add 9 to
both sides
|
y - 9 = 50
y - 9
+ 9
= 50
+ 9
y = 59 |
To check:
y - 9 = 50
59 - 9 = 50
50 = 50√ |
Solve for y:
2.3 + y = 5.3
Step One:
Knowing:
2.3y + y means add 2.3 to "y" , and
subtraction is the inverse operation
Step Two: Subtract
2.3 from both sides
|
2.3 + y = 5.3
2.3
- 2.3
+ y = 5.3 - 2.3
y = 3.0 or 3 |
To check:
2.3 + y = 5.3
2.3 + 3 = 5.3
5.3 = 5.3√ |
|
Solve for y:
5y = 25
Step One: Knowing:
5y means multiply "y" by 5, and
division is the inverse operation
Step Two: Divide
both sides by 5
|
5y = 25
5y/5
= 25/5
y = 5 |
To check:
5y = 25
5(5) = 25
25 = 25√ |
|
Solve for y:
60 + y = 200
Step One: Knowing:
60 + y means add 60 to "y", and
subtraction is the inverse operation
Step Two: Subtract
60 from both sides
|
60 + y = 200
60
- 60
+ y = 200 - 60
y = 140 |
To check:
60 + y = 200
60 + 140 = 200
200 = 200√ |
